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Q1. - (Topic 1)
How does a switch differ from a hub?
A. A switch does not induce any latency into the frame transfer time.
B. A switch tracks MAC addresses of directly-connected devices.
C. A switch operates at a lower, more efficient layer of the OSI model.
D. A switch decreases the number of broadcast domains.
E. A switch decreases the number of collision domains.
Answer: B
Explanation:
Some of the features and functions of a switch include:
A switch is essentially a fast, multi-port bridge, which can contain dozens of ports.
Rather than creating two collision domains, each port creates its own collision domain.
In a network of twenty nodes, twenty collision domains exist if each node is plugged into its
own switch port.
If an uplink port is included, one switch creates twenty-one single-node collision domains.
A switch dynamically builds and maintains a Content-Addressable Memory (CAM) table,
holding all of the necessary MAC information for each port.
For a detailed description of how switches operate, and their key differences to hubs, see
the reference link below.
Reference: http://www.cisco.com/warp/public/473/lan-switch-cisco.shtml
Q2. DRAG DROP - (Topic 5)
Drag the appropriate command on the left to the configuration task it accomplishes. (Not all options are used.)
Answer:
Q3. CORRECT TEXT - (Topic 6)
Answer: Router>enable
Router#config terminal Router(config)#hostname Apopka 2) Enable-secret password (cisco10): Apopka(config)#enable secret cisco10 3) Set the console password to RouterPass: Apopka(config)#line console 0 Apopka(config-line)#password RouterPass Apopka(config-line)#login Apopka(config-line)#exit 4) Set the Telnet password to scan90: Apopka(config)#line vty 0 4 Apopka(config-line)#password scan90 Apopka(config-line)#login Apopka(config-line)#exit 5) Configure Ethernet interface (on the right) of router Apopka: The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can find out the increment by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111 1111.1110 0000. Pay more attention to the last bit 1 because it tells us the increment, using the formula: Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment = 25 = 32. Therefore: Increment: 32 Network address: 209.165.201.0 Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the previous IP - 209.165.201.31 - is the broadcast address of the first subnet). -> The second assignable host address of this subnetwork is 209.165.201.2/27 Assign the second assignable host address to Fa0/0 interface of Apopka router: Apopka(config)#interface Fa0/0 Apopka(config-if)#ip address 209.165.201.2 255.255.255.224 Apopka(config-if)#no shutdown Apopka(config-if)#exit 6) Configure Serial interface (on the left) of router Apopka: Using the same method to find out the increment of the Serial network: Serial network 192.0.2.128/28: Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000) Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address of this subnet) Broadcast address: 192.0.2.143 -> The last assignable host address in this subnet is 192.0.2.142/28. Assign the last assignable host address to S0/0/0 interface of Apopka router: Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful) Apopka(config-if)#ip address 192.0.2.142 255.255.255.240 Apopka(config-if)#no shutdown Apopka(config-if)#exit 7) Configure RIP v2 routing protocol: Apopka(config)#router rip Apopka(config-router)#version 2 Apopka(config-router)#network 209.165.201.0 Apopka(config-router)#network 192.0.2.128 Apopka(config-router)#end Save the configuration: Apopka#copy running-config startup-config Finally, you should use the ping command to verify all are working properly!
Topic 7, Mix Questions
Q4. - (Topic 3)
What is the default administrative distance of OSPF?
A. 90
B. 100
C. 110
D. 120
Answer: C
Explanation:
Administrative distance is the feature that routers use in order to select the best path when there are two or more different routes to the same destination from two different routing protocols. Administrative distance defines the reliability of a routing protocol. Each routing protocol is prioritized in order of most to least reliable (believable) with the help of an administrative distance value.
Default Distance Value Table
This table lists the administrative distance default values of the protocols that Cisco supports:
Q5. - (Topic 1)
Refer to the exhibit.
SwitchA receives the frame with the addressing shown in the exhibit. According to the command output also shown in the exhibit, how will SwitchA handle this frame?
A. It will drop the frame.
B. It will forward the frame out port Fa0/6 only.
C. It will forward the frame out port Fa0/3 only.
D. It will flood the frame out all ports.
E. It will flood the frame out all ports except Fa0/3.
Answer: E
Explanation:
When frame receives the frame, it checks the source address on MAC table if MAC address found in MAC table it tries to forward if not in MAC table adds the Address on MAC table. After checking the source address, it checks the destination address on MAC table, if MAC address found on MAC table it forwards to proper ports otherwise floods on all ports except the source port.
Q6. - (Topic 3)
Which statements are TRUE regarding Internet Protocol version 6 (IPv6) addresses? (Choose three.)
A. An IPv6 address is divided into eight 16-bit groups.
B. A double colon (::) can only be used once in a single IPv6 address.
C. IPv6 addresses are 196 bits in length.
D. Leading zeros cannot be omitted in an IPv6 address.
E. Groups with a value of 0 can be represented with a single 0 in IPv6 address.
Answer: A,B,E
Explanation:
IPv6 addresses are divided into eight 16-bit groups, a double colon (::) can only be used
once in an IPv6 address, and groups with a value of 0 can be represented with a single 0 in
an IPv6 address.
The following statements are also true regarding IPv6 address:
IPv6 addresses are 128 bits in length.
Eight 16-bit groups are divided by a colon (:).
Multiple groups of 16-bit 0s can be represented with double colon (::).
Double colons (::) represent only 0s.
Leading zeros can be omitted in an IPv6 address.
The option stating that IPv6 addresses are 196 bits in length is incorrect. IPv6 addresses
are 128 bits in length.
The option stating that leading zeros cannot be omitted in an IPv6 address is incorrect.
Leading zeros can be omitted in an IPv6 address.
Q7. - (Topic 3)
Given an IP address of 192.168.1.42 255.255.255.248, what is the subnet address?
A. 192.168.1.8/29
B. 192.168.1.32/27
C. 192.168.1.40/29
D. 192.168.1.16/28
E. 192.168.1.48/29
Answer: C
Explanation:
248 mask uses 5 bits (1111 1000)
42 IP in binary is (0010 1010)
The base subnet therefore is the lowest binary value that can be written without changing
the output of an AND operation of the subnet mask and IP...
1111 1000 AND
0010 1010 equals
0010 1000 - which is .40
/24 is standard class C mask.
Adding the 5 bits from the .248 mask gives /29
Q8. - (Topic 3)
Identify the four valid IPv6 addresses. (Choose four.)
A. ::
B. ::192:168:0:1
C. 2000::
D. 2001:3452:4952:2837::
E. 2002:c0a8:101::42
F. 2003:dead:beef:4dad:23:46:bb:101
Answer: A,B,E,F
Explanation:
http://www.intermapper.com/ipv6validator http://www.ripe.net/lir-services/new-lir/ipv6_reference_card.pdf
Q9. - (Topic 5)
Refer to the exhibit.
A person is trying to send a file from a host on Network A of the JAX Company to a server
on Network Z of the XYZ Company. The file transfer fails. The host on Network A can communicate with other hosts on Network A.
Which command, issued from router RTA, would be the most useful for troubleshooting this problem?
A. show flash:
B. show history
C. show version
D. show interfaces
E. show controllers serial
Answer: D
Explanation:
The most useful thing to check on RTA would be the show interfaces command to see if the interface toward the WAN link is up. The most likely scenario is that the local LAN interface is up, but the other interface toward the XYZ company is down.
Q10. - (Topic 3)
An administrator is working with the 192.168.4.0 network, which has been subnetted with a /26 mask. Which two addresses can be assigned to hosts within the same subnet? (Choose two.)
A. 192.168.4.61
B. 192.168.4.63
C. 192.168.4.67
D. 192.168.4.125
E. 192.168.4.128
F. 192.168.4.132
Answer: C,D
Explanation:
Increment: 64 (/26 = 11111111.11111111.11111111.11000000)
The IP 192.168.4.0 belongs to class C. The default subnet mask of class C is /24 and it has
been subnetted with a /26 mask so we have 2(26-24).= 22.= 4 sub-networks:
1st subnet: 192.168.4.0 (to 192.168.4.63)
2nd subnet: 192.168.4.64 (to 192.168.4.127)
3rd subnet: 192.168.4.128 (to 192.168.4.191)
4th subnet: 192.168.4.192 (to 192.168.4.225)
In all the answers above, only answer C and D are in the same subnet.
Therefore only IPs in this range can be assigned to hosts.