Act now and download your Cisco ccda 200 310 official cert guide pdf test today! Do not waste time for the worthless Cisco ccda 200 310 official cert guide tutorials. Download Abreast of the times Cisco Designing for Cisco Internetwork Solutions exam with real questions and answers and begin to learn Cisco ccda 200 310 official cert guide download with a classic professional.
2026 New 200-310 Exam Dumps with PDF and VCE Free: https://www.2passeasy.com/dumps/200-310/
Q1. You want to gather as much detail as possible during a network audit, to include data time stamping across a large number of interfaces, customized according to interface, with a minimal impact on the network devices themselves. Which tool would you use to meet these requirements?
A. RMON
B. SNMPv3
C. NetFlow
D. Cisco Discovery Protocol
Answer: C
Explanation:
NetFlow provides extremely granular and accurate traffic measurements and a high-level collection of aggregated traffic. The output of netflow information is displayed via the show ip cache flow command on routers. The Table shows a description of the fields for NetFlow output.
Table. Netflow Output escription
Q2. Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 8 kHz x 4-bit code words
B. 8 kHz x 8-bit code words
C. 2 x 4-bit code words x 8 kHz
D. 2 x 4 kHz x 8-bit code words
Answer: D
Explanation: While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400 Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for voice is 4000 Hz. According to Nyquist theory, we must double the highest frequency, so 2x4kHz = 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second = 64 Kilobit per second = 64 Kbps)
Link: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem
Note:
Nyquist theory:
“When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency must be greater than twice the bandwidth of the input signal in order to be able to reconstruct the original perfectly from the sampled version.”
Q3. Which three terms describe the primary functions of the distribution layer of the campus network design hierarchy? (Choose three.)
A. provides end-user connectivity
B. provides high speed transport
C. provides QoS services
D. enforces security policies
E. provides WAN connections
F. connects access devices to the core backbone
Answer: C,D,F
Explanation: Link: http://www.cisco.com/en/US/docs/solutions/Enterprise/Campus/campover.html#wp708979
Q4. DRAG DROP
Answer:
Q5. What significant advantage does EIGRP have over OSPF?
A. easy summarization
B. shorter convergence times
C. single area operation
D. low processor utilization
Answer: B
Q6. A network engineer has been asked to follow a top down design approach. What layer of the OSI model is used to start the design?
A. physical
B. network
C. transport
D. application
Answer: D
Q7. A network engineer is attempting to separate routing domains using a virtualization technology. What protocol can be configured to perform this task?
A. VLAN
B. VSAN
C. VRF
D. VPC
Answer: C
Q8. A network engineer must implement a design where LAN clients are to connect.to various access layer devices, while remaining on the same VLAN . What type of design would support this requirement?
A. routed
B. switched
C. tunneled
D. virtual
Answer: B
Q9. What three primary sources of information are needed to perform a network audit? (Choose three.)
A. existing documentation
B. new documentation
C. existing network management software
D. new network management tools
E. management personnel
F. technical personnel
Answer: A,C,D
Q10. Which three are valid Layer 2 access designs? (Choose three.)
A. Looped Triangle
B. Looped Square
C. Looped U
D. Loop-Free Triangle
E. Loop-Free Square
F. Loop-Free U
Answer: A,B,F