Exam Code: ccnp route 300 101 pdf (Practice Exam Latest Test Questions VCE PDF)
Exam Name: Implementing Cisco IP Routing
Certification Provider: Cisco
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Q1. After you review the output of the command show ipv6 interface brief, you see that several IPv6 addresses have the 16-bit hexadecimal value of "FFFE" inserted into the address. Based on this information, what do you conclude about these IPv6 addresses?
A. IEEE EUI-64 was implemented when assigning IPv6 addresses on the device.
B. The addresses were misconfigured and will not function as intended.
C. IPv6 addresses containing "FFFE" indicate that the address is reserved for multicast.
D. The IPv6 universal/local flag (bit 7) was flipped.
E. IPv6 unicast forwarding was enabled, but IPv6 Cisco Express Forwarding was disabled.
Answer: A
Explanation:
Extended Unique Identifier (EUI), as per RFC2373, allows a host to assign iteslf a unique 64-
Bit IP Version 6 interface identifier (EUI-64). This feature is a key benefit over IPv4 as it eliminates the
need of manual configuration or DHCP as in the world of IPv4. The IPv6 EUI-64 format address is obtained
through the 48-bit MAC address. The Mac address is first separated into two 24-bits, with one being OUI
(Organizationally Unique Identifier) and the other being NIC specific. The 16-bit 0xFFFE is then inserted
between these two 24-bits to for the 64-bit EUI address. IEEE has chosen FFFE as a reserved value which
can only appear in EUI-64 generated from the an EUI-48 MAC address. Here is an example showing how
a the Mac Address is used to generate EUI.
Next, the seventh bit from the left, or the universal/local (U/L) bit, needs to be inverted. This bit identifies whether this interface identifier is universally or locally administered. If 0, the address is locally
administered and if 1, the address is globally unique. It is worth noticing that in the OUI portion, the globally
unique addresses assigned by the IEEE has always been set to 0 whereas the locally created addresses
has 1 configured. Therefore, when the bit is inverted, it maintains its original scope (global unique address
is still global unique and vice versa). The reason for inverting can be found in RFC4291 section 2.5.1.
Once the above is done, we have a fully functional EUI-64 format address.
Reference: https://
supportforums.cisco.com/document/100566/understanding-ipv6-eui-64-bit- address
Q2. CORRECT TEXT
You are a network engineer with ROUTE.com, a small IT company. They have recently merged two organizations and now need to merge their networks as shown in the topology exhibit. One network is using OSPF as its IGP and the other is using EIGRP as its IGP. R4 has been added to the existing OSPF network to provide the interconnect between the OSPF and EIGRP networks. Two links have been added that will provide redundancy.
The network requirements state that you must be able to ping and telnet from loopback 101 on R1 to the OPSF domain test address of 172.16.1.100. All traffic must use the shortest path that provides the greatest bandwidth. The redundant paths from the OSPF network to the EIGRP network must be available in case of a link failure. No static or default routing is allowed in either network.
A previous network engineer has started the merger implementation and has successfully assigned and verified all IP addressing and basic IGP routing. You have been tasked with completing the implementation and ensuring that the network requirements are met. You may not remove or change any of the configuration commands currently on any of the routers. You may add new commands or change default values.
Answer: First we need to find out 5 parameters (Bandwidth, Delay, Reliability, Load, MTU) of the s0/0/0 interface (the interface of R2 connected to R4) for redistribution:
R2#show interface s0/0/0
Write down these 5 parameters, notice that we have to divide the Delay by 10 because the metric unit is in tens of microsecond. For example, we get Bandwidth=1544 Kbit, Delay=20000 us, Reliability=255, Load=1, MTU=1500 bytes then we would redistribute as follows:
R2#config terminal
R2(config)# router ospf 1
R2(config-router)# redistribute eigrp 100 metric-type 1 subnets
R2(config-router)#exit
R2(config-router)#router eigrp 100
R2(config-router)#redistribute ospf 1 metric 1544 2000 255 1 1500
Note: In fact, these parameters are just used for reference and we can use other parameters with
no problem.
If the delay is 20000us then we need to divide it by 10, that is 20000 / 10 = 2000)
For R3 we use the show interface fa0/0 to get 5 parameters too
R3#show interface fa0/0
For example we get Bandwidth=10000 Kbit, Delay=1000 us, Reliability=255, Load=1, MTU=1500 bytes
R3#config terminal
R3(config)#router ospf 1
R3(config-router)#redistribute eigrp 100 metric-type 1 subnets
R3(config)#exit
R3(config-router)#router eigrp 100
R3(config-router)#redistribute ospf 1 metric 10000 100 255 1 1500
Finally you should try to “show ip route” to see the 172.16.100.1 network (the network behind R4)
in the routing table of R1 and make a ping from R1 to this network.
Note: If the link between R2 and R3 is FastEthernet link, we must put the command below under
EIGRP process to make traffic from R1 to go through R3 (R1 -> R2 -> R3 -> R4), which is better
than R1 -> R2 -> R4.
R2(config-router)# distance eigrp 90 105
This command sets the Administrative Distance of all EIGRP internal routes to 90 and all EIGRP external routes to 105, which is smaller than the Administrative Distance of OSPF (110) -> the link between R2 & R3 will be preferred to the serial link between R2 & R4. Note: The actual OPSF and EIGRP process numbers may change in the actual exam so be sure to use the actual correct values, but the overall solution is the same.
Q3. Refer to the exhibit. After configuring GRE between two routers running OSPF that are connected to each other via a WAN link, a network engineer notices that the two routers cannot establish the GRE tunnel to begin the exchange of routing updates. What is the reason for this?
A. Either a firewall between the two routers or an ACL on the router is blocking IP protocol number 47.
B. Either a firewall between the two routers or an ACL on the router is blocking UDP 57.
C. Either a firewall between the two routers or an ACL on the router is blocking TCP 47.
D. Either a firewall between the two routers or an ACL on the router is blocking IP protocol number 57.
Answer: A
Explanation:
Q4. A network engineer notices that transmission rates of senders of TCP traffic sharply increase and decrease simultaneously during periods of congestion. Which condition causes this?
A. global synchronization
B. tail drop
C. random early detection
D. queue management algorithm
Answer: A
Explanation:
TCP global synchronization in computer networks can happen to TCP/IP flows during periods of
congestion because each sender will reduce their transmission rate at the same time when packet loss
occurs. Routers on the Internet normally have packet queues, to allow them to hold packets when the
network is busy, rather than discarding them. Because routers have limited resources, the size of these
queues is also limited. The simplest technique to limit queue size is known as tail drop. The queue is
allowed to fill to its maximum size, and then any new packets are simply discarded, until there is space in
the queue again. This causes problems when used on TCP/IP routers handling multiple TCP streams,
especially when bursty traffic is present. While the network is stable, the queue is constantly full, and there
are no problems except that the full queue results in high latency. However, the introduction of a sudden
burst of traffic may cause large numbers of established, steady streams to lose packets simultaneously.
Reference: http://en.wikipedia.org/wiki/TCP_global_synchronization
Q5. A router receives a routing advertisement for the same prefix and subnet from four different routing protocols. Which advertisement is installed in the routing table?
A. RIP
B. OSPF
C. iBGP
D. EIGRP
Answer: D
Explanation:
Q6. Which three characteristics are shared by subinterfaces and associated EVNs? (Choose three.)
A. IP address
B. routing table
C. forwarding table
D. access control lists
E. NetFlow configuration
Answer: A,B,C
Explanation:
A trunk interface can carry traffic for multiple EVNs. To simplify the configuration process, all
the subinterfaces and associated EVNs have the same IP address assigned. In other words, the trunk
interface is identified by the same IP address in different EVN contexts. This is accomplished as a result of
each EVN having a unique routing and forwarding table, thereby enabling support for overlapping IP
addresses across multiple EVNs. Reference: http://www.cisco.com/en/US/docs/ios-xml/ios/evn/
configuration/xe-3sg/evn- overview.pdf
Q7. A network engineer executes the show crypto ipsec sa command. Which three pieces of information are displayed in the output? (Choose three.)
A. inbound crypto map
B. remaining key lifetime
C. path MTU
D. tagged packets
E. untagged packets
F. invalid identity packets
Answer: A,B,C
Explanation:
show crypto ipsec sa This command shows IPsec SAs built between peers. The encrypted
tunnel is built between 12.1.1.1 and 12.1.1.2 for traffic that goes between networks 20.1.1.0 and 10.1.1.0.
You can see the two Encapsulating Security Payload (ESP) SAs built inbound and outbound.
Authentication Header (AH) is not used since there are
no AH SAs.
This output shows an example of the show crypto ipsec sa command (bolded ones found in answers for
this question).
interface: FastEthernet0
Crypto map tag: test, local addr. 12.1.1.1
local ident (addr/mask/prot/port): (20.1.1.0/255.255.255.0/0/0) remote ident (addr/mask/prot/port):
(10.1.1.0/255.255.255.0/0/0) current_peer: 12.1.1.2
PERMIT, flags={origin_is_acl,}
#pkts encaps: 7767918, #pkts encrypt: 7767918, #pkts digest 7767918 #pkts decaps: 7760382, #pkts
decrypt: 7760382, #pkts verify 7760382 #pkts compressed:
0, #pkts decompressed: 0
#pkts not compressed: 0, #pkts compr. failed: 0,
#pkts decompress failed: 0, #send errors 1, #recv errors 0 local crypto endpt.: 12.1.1.1, remote crypto
endpt.: 12.1.1.2 path mtu 1500, media mtu 1500
current outbound spi: 3D3
inbound esp sas:
spi: 0x136A010F(325714191)
transform: esp-3des esp-md5-hmac ,
in use settings ={Tunnel, }
slot: 0, conn id: 3442, flow_id: 1443, crypto map: test sa timing: remaining key lifetime (k/sec):
(4608000/52) IV size: 8 bytes
replay detection support: Y
inbound ah sas:
inbound pcp sas:
inbound pcp sas:
outbound esp sas:
spi: 0x3D3(979)
transform: esp-3des esp-md5-hmac ,
in use settings ={Tunnel, }
slot: 0, conn id: 3443, flow_id: 1444, crypto map: test sa timing: remaining key lifetime (k/sec):
(4608000/52) IV size: 8 bytes
replay detection support: Y
outbound ah sas:
outbound pcp sas:
Reference: http://www.cisco.com/c/en/us/support/docs/security-vpn/ipsec-negotiation-ike- protocols/5409-
ipsec-debug-00.html
Q8. A network engineer is configuring a routed interface to forward broadcasts of UDP 69, 53, and 49 to 172.20.14.225. Which command should be applied to the configuration to allow this?
A. router(config-if)#ip helper-address 172.20.14.225
B. router(config-if)#udp helper-address 172.20.14.225
C. router(config-if)#ip udp helper-address 172.20.14.225
D. router(config-if)#ip helper-address 172.20.14.225 69 53 49
Answer: A
Explanation:
To let a router forward broadcast packet the command ip helper-address can be used. The broadcasts will
be forwarded to the unicast address which is specified with the ip helper command.
ip helper-address {ip address}
When configuring the ip helper-address command, the following broadcast packets will be forwarded by
the router by default:
TFTP - UDP port 69
Domain Name System (DNS) UDP port 53
Time service - port 37
NetBIOS Name Server - port 137
NetBIOS Datagram Server - port 138
Bootstrap Protocol (BOOTP) - port 67
TACACS UDP port 49 Reference: http://www.cisco-faq.com/163/forward_udp_broadcas.html
Topic 6, Infrastructure Services
61. A network engineer is configuring SNMP on network devices to utilize one-way SNMP notifications. However, the engineer is not concerned with authentication or encryption. Which command satisfies the requirements of this scenario?
A. router(config)#snmp-server host 172.16.201.28 traps version 2c CISCORO
B. router(config)#snmp-server host 172.16.201.28 informs version 2c CISCORO
C. router(config)#snmp-server host 172.16.201.28 traps version 3 auth CISCORO
D. router(config)#snmp-server host 172.16.201.28 informs version 3 auth CISCORO
Q9. CORRECT TEXT [SIMULATION]
Route.com is a small IT corporation that is attempting to implement the network shown in the exhibit. Currently the implementation is partially completed. OSPF has been configured on routers Chicago and NewYork. The SO/O interface on Chicago and the SO/1 interface on NewYork are in Area 0. The loopbackO interface on NewYork is in Area 1. However, they cannot ping from the serial interface of the Seattle router to the loopback interface of the NewYork router. You have been asked to complete the implementation to allow this ping.
ROUTE.com's corporate implementation guidelines require:
. The OSPF process ID for all routers must be 10.
. The routing protocol for each interface must be enabled under the routing process.
. The routing protocol must be enabled for each interface using the most specific wildcard mask possible.
.The serial link between Seattle and Chicago must be in OSPF area 21.
.OSPF area 21 must not receive any inter-area or external routes.
Network Information
Seattle
S0/0 192.168.16.5/30 - Link between Seattle and Chicago
Secret Password: cisco
Chicago
S0/0 192.168.54.9/30 - Link between Chicago and NewYork
S0/1 192.168.16.6/30 - Link between Seattle and Chicago Secre Password: cisco
NewYork
S0/1 192.168.54.10/30 - Link between Chicago and NewYork
Loopback0 172.16.189.189
Secret Password: cisco
Answer: Here is the solution below:
Explanation:
Note: In actual exam, the IP addressing, OSPF areas and process ID, and router hostnames may change, but the overall solution is the same.
Seattle’s S0/0 IP Address is 192.168.16.5/30. So, we need to find the network address and wildcard mask of 192.168.16.5/30 in order to configure the OSPF.
IP Address: 192.168.16.5 /30
Subnet Mask: 255.255.255.252
Here subtract 252 from 2565, 256-252 = 4, hence the subnets will increment by 4.
First, find the 4th octet of the Network Address:
The 4th octet of IP address (192.168.16.5) belongs to subnet 1 (4 to 7).
Network Address: 192.168.16.4
Broadcast Address: 192.168.16.7
Lets find the wildcard mask of /30.
Subnet Mask: (Network Bits – 1’s, Host Bits – 0’s)
Lets find the wildcard mask of /30:
Now we configure OSPF using process ID 10 (note the process ID may change to something else in real exam).
Seattle>enable
Password: cisco
Seattle#conf t
Seattle(config)#router ospf 10
Seattle(config-router)#network 192.168.16.4 0.0.0.3 area 21
One of the tasks states that area 21 should not receive any external or inter-area routes (except
the default route).
Seattle(config-router)#area 21 stub
Seattle(config-router)#end
Seattle#copy run start
Chicago Configuration:
Chicago>enable
Password: cisco
Chicago#conf t
Chicago(config)#router ospf 10
We need to add Chicago’s S0/1 interface to Area 21
Chicago(config-router)#network 192.168.16.4 0.0.0.3 area 21
Again, area 21 should not receive any external or inter-area routes (except the default route).
In order to accomplish this, we must stop LSA Type 5 if we don’t want to send external routes. And
if we don’t want to send inter-area routes, we have to stop LSA Type 3 and Type 4. Therefore we
want to configure area 21 as a totally stubby area.
Chicago(config-router)#area 21 stub no-summary
Chicago(config-router)#end
Chicago#copy run start
The other interface on the Chicago router is already configured correctly in this scenario, as well
as the New York router so there is nothing that needs to be done on that router.
Q10. A network engineer is notified that several employees are experiencing network performance related issues, and bandwidth-intensive applications are identified as the root cause. In order to identify which specific type of traffic is causing this slowness, information such as the source/destination IP and Layer 4 port numbers is required. Which feature should the engineer use to gather the required information?
A. SNMP
B. Cisco IOS EEM
C. NetFlow
D. Syslog
E. WCCP
Answer: C
Explanation:
NetFlow Flows Key Fields
A network flow is identified as a unidirectional stream of packets between a given source and destination--
both are defined by a network-layer IP address and
transport-layer source and destination port numbers. Specifically, a flow is identified as the combination of
the following key fields:
Source IP address
Destination IP address
Source Layer 4 port number
Destination Layer 4 port number
Layer 3 protocol type
Type of service (ToS)
Input logical interface Reference: http://www.cisco.com/en/US/docs/ios-xml/ios/netflow/configuration/12-4t/
cfg-nflow- data-expt.html